source: rtems/cpukit/libcrypt/crypt-md5.c

Last change on this file was 6fe3acd0, checked in by Pedro F. Giffuni <pfg@…>, on 11/26/17 at 02:00:33

lib: further adoption of SPDX licensing ID tags.

Mainly focus on files that use BSD 2-Clause license, however the tool I
was using mis-identified many licenses so this was mostly a manual - error
prone - task.

The Software Package Data Exchange (SPDX) group provides a specification
to make it easier for automated tools to detect and summarize well known
opensource licenses. We are gradually adopting the specification, noting
that the tags are considered only advisory and do not, in any way,
superceed or replace the license texts.

  • Property mode set to 100644
File size: 4.6 KB
Line 
1/*-
2 * SPDX-License-Identifier: BSD-2-Clause-FreeBSD
3 *
4 * Copyright (c) 2003 Poul-Henning Kamp
5 * All rights reserved.
6 *
7 * Redistribution and use in source and binary forms, with or without
8 * modification, are permitted provided that the following conditions
9 * are met:
10 * 1. Redistributions of source code must retain the above copyright
11 *    notice, this list of conditions and the following disclaimer.
12 * 2. Redistributions in binary form must reproduce the above copyright
13 *    notice, this list of conditions and the following disclaimer in the
14 *    documentation and/or other materials provided with the distribution.
15 *
16 * THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND
17 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
18 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
19 * ARE DISCLAIMED.  IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
20 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
21 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
22 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
23 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
24 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
25 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
26 * SUCH DAMAGE.
27 */
28
29#include <sys/cdefs.h>
30__FBSDID("$FreeBSD$");
31
32#include <sys/types.h>
33
34#include <md5.h>
35#include <stdio.h>
36#include <string.h>
37#include <unistd.h>
38
39#include <crypt.h>
40
41#define MD5_SIZE 16
42
43/*
44 * UNIX password
45 */
46
47char *
48crypt_md5_r(const char *pw, const char *salt, struct crypt_data *data)
49{
50        MD5_CTX ctx,ctx1;
51        unsigned long l;
52        int sl, pl;
53        u_int i;
54        u_char final[MD5_SIZE];
55        const char *sp, *ep;
56        char *passwd = &data->buffer[0], *p;
57        static const char magic[] = "$1$";
58
59        /* Refine the Salt first */
60        sp = salt;
61
62        /* If it starts with the magic string, then skip that */
63        if(!strncmp(sp, magic, strlen(magic)))
64                sp += strlen(magic);
65
66        /* It stops at the first '$', max 8 chars */
67        for(ep = sp; *ep && *ep != '$' && ep < (sp + 8); ep++)
68                continue;
69
70        /* get the length of the true salt */
71        sl = ep - sp;
72
73        MD5Init(&ctx);
74
75        /* The password first, since that is what is most unknown */
76        MD5Update(&ctx, (const u_char *)pw, strlen(pw));
77
78        /* Then our magic string */
79        MD5Update(&ctx, (const u_char *)magic, strlen(magic));
80
81        /* Then the raw salt */
82        MD5Update(&ctx, (const u_char *)sp, (u_int)sl);
83
84        /* Then just as many characters of the MD5(pw,salt,pw) */
85        MD5Init(&ctx1);
86        MD5Update(&ctx1, (const u_char *)pw, strlen(pw));
87        MD5Update(&ctx1, (const u_char *)sp, (u_int)sl);
88        MD5Update(&ctx1, (const u_char *)pw, strlen(pw));
89        MD5Final(final, &ctx1);
90        for(pl = (int)strlen(pw); pl > 0; pl -= MD5_SIZE)
91                MD5Update(&ctx, (const u_char *)final,
92                    (u_int)(pl > MD5_SIZE ? MD5_SIZE : pl));
93
94        /* Don't leave anything around in vm they could use. */
95        memset(final, 0, sizeof(final));
96
97        /* Then something really weird... */
98        for (i = strlen(pw); i; i >>= 1)
99                if(i & 1)
100                    MD5Update(&ctx, (const u_char *)final, 1);
101                else
102                    MD5Update(&ctx, (const u_char *)pw, 1);
103
104        /* Now make the output string */
105        strcpy(passwd, magic);
106        strncat(passwd, sp, (u_int)sl);
107        strcat(passwd, "$");
108
109        MD5Final(final, &ctx);
110
111        /*
112         * and now, just to make sure things don't run too fast
113         * On a 60 Mhz Pentium this takes 34 msec, so you would
114         * need 30 seconds to build a 1000 entry dictionary...
115         */
116        for(i = 0; i < 1000; i++) {
117                MD5Init(&ctx1);
118                if(i & 1)
119                        MD5Update(&ctx1, (const u_char *)pw, strlen(pw));
120                else
121                        MD5Update(&ctx1, (const u_char *)final, MD5_SIZE);
122
123                if(i % 3)
124                        MD5Update(&ctx1, (const u_char *)sp, (u_int)sl);
125
126                if(i % 7)
127                        MD5Update(&ctx1, (const u_char *)pw, strlen(pw));
128
129                if(i & 1)
130                        MD5Update(&ctx1, (const u_char *)final, MD5_SIZE);
131                else
132                        MD5Update(&ctx1, (const u_char *)pw, strlen(pw));
133                MD5Final(final, &ctx1);
134        }
135
136        p = passwd + strlen(passwd);
137
138        l = (final[ 0]<<16) | (final[ 6]<<8) | final[12];
139        _crypt_to64(p, l, 4); p += 4;
140        l = (final[ 1]<<16) | (final[ 7]<<8) | final[13];
141        _crypt_to64(p, l, 4); p += 4;
142        l = (final[ 2]<<16) | (final[ 8]<<8) | final[14];
143        _crypt_to64(p, l, 4); p += 4;
144        l = (final[ 3]<<16) | (final[ 9]<<8) | final[15];
145        _crypt_to64(p, l, 4); p += 4;
146        l = (final[ 4]<<16) | (final[10]<<8) | final[ 5];
147        _crypt_to64(p, l, 4); p += 4;
148        l = final[11];
149        _crypt_to64(p, l, 2); p += 2;
150        *p = '\0';
151
152        /* Don't leave anything around in vm they could use. */
153        memset(final, 0, sizeof(final));
154
155        return (passwd);
156}
157
158struct crypt_format crypt_md5_format =
159    CRYPT_FORMAT_INITIALIZER(crypt_md5_r, "$1$");
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